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sashaice [31]
3 years ago
13

A firework is launched from the ground at a velocity of 180 feet per second. its height after t (t is variable) seconds is given

by the polynomial -16t^2+180t. what is the height of the firework after 2 seconds?
very urgent, please help!!
Mathematics
1 answer:
VMariaS [17]3 years ago
7 0

-16t² + 180t

-16(2)² + 180(2)

-64 + 360

The fireworks height after 2 seconds is 296 feet

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Use an algebraic equation to find the measure of each angle that is represented in terms of x.
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Explanation:

Given that the two angles are (11x-26)° and (7x+26)°

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<u>Measure of angles:</u>

From the figure, it is obvious that the two angles are vertically opposite angles.

By definition, we know that, the vertically opposite angles are always equal.

To determine the measure of each angle, we shall first find the value of x.

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Now, substituting x=13 in the angle (11x-26)°, we get,

(11(13)-26)^{\circ}=(143-26)^{\circ}

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Similarly, substituting x=13 in the angle (7x+26)°, we get,

(7x+26)^{\circ}=(7(13)+26)^{\circ}

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d

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fredd [130]

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