Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
To solve this problem, we first have to find the slope of the two given points. To find the slope, we have to use slope intercept form, which is y₂ - y₁ divided by x₂ - x₁. We substitute each variable for its corresponding value, and we'll get -2 - (-3) divided by 4-1. If we simplify the expression, we'll get 1/3. Next, we plug in the slope and one ordered pair into the equation and we get -3 = 1/3 * 1 + b. We should solve for b and we end up with -3 1/3 = b. Therefore, the equation is y = 1/3x - 3 1/3.
Answer: 5, -5
Step-by-step explanation:
There are only 2 square roots of 25: plus and minus 5.
-1 is the answer or your answer is gonna be false
