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KonstantinChe [14]

3 years ago

9

Please hep me with this if you can you are amazing and the best thank you

1 answer:

blondinia [14]3 years ago

3 0

Answer:

Option 1

Y=2x+116

Option 2

Y=2x+110

Step-by-step explanation:

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What is 8^-2 times a^7

Anna71 [15]

Answer:

a⁷

---

64

Step-by-step explanation:

3 0

3 years ago

3(2x+5)=3×+4x<br>how di i solve this step by step

BaLLatris [955]

1. distribute the 3 into the parentheses, so you would now have 6x+15=3x+4
2. combine like terms on the right side , so now you have 6x+15=7x
3. subtract the 6 from the left side so it cancels out and also subtract the 6 from the 7 so now you have 15=x
hope this answers your question !

7 0

3 years ago

Sketch the graph of y = negative 2 x squared + x + 1 using your graphing calculator. What are the x-intercepts of this graph? a.

lions [1.4K]

The x-intercept is (1, 0) and (-0.5, 0).

The correct option is (a)

<h3>What is intercept?</h3>

The x-intercept is the point where a line crosses the x-axis, and the y-intercept is the point where a line crosses the y-axis.

Given function is:

f(x)= $-2x^{2}+x+1$

So, The graph of this equation is attaches below.

The x- intercepts of this graph

$\mathrm{X\:Intercepts}:\:\left(-\frac{1}{2},\:0\right),\:\left(1,\:0\right)$

or

X intercepts: (1, 0) and (-0.5, 0)

Hence, the x-intercept is (1, 0) and (-0.5, 0).

Learn more about intercept here:

brainly.com/question/14180189

#SPJ1

4 0

2 years ago

A car traveling east at a constant rate of 33 mi/hr passes through an intersection at 10 A.M. A truck traveling north at a const

Rufina [12.5K]

Answer:52.33 m/s

Step-by-step explanation:

Given

Speed of car $v_1=33 mi/hr$

Speed of truck $v_2=42 mi/hr$

Distance traveled by car in 1 hr is 33 mi

Therefore after 11 am distance of car and truck from Junction in time t is

Car $=33+33t$

truck $=42 t$

Let D be the distance between them

$D^2=42t^2+(33+33t)^2$ ------------1

at $t= 2 hr$

$D^2=(42\times 2)^2+(33+66)^2$

$D=129.83 miles$

To get how fast distance between them is increasing differentiate 1 we get

$2D\frac{\mathrm{d} D}{\mathrm{d} t}=2\cdot(42)^2t+2\cdot 33^2(1+t)$

$\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{42^2t+33^2\left ( 1+t\right )}{D}$

$\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{1764\times 2+1089\times 3}{D}$

$\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{6795}{129.83}=52.33 m/s$

3 0

4 years ago

Read 2 more answers

The proper angle for a ladder is about 75 from the ground. Suppose you have a 6 foot ladder. How high

Virty [35]

Answer:

450

Step-by-step explanation:

75 x 6 is 450 so the answer is 450

7 0

3 years ago