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Fantom [35]
3 years ago
5

I need help!!! Please help ASAP!

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

180 ≥ 45 + 15x

<u> -45</u>   <u>-45        </u>

135 ≥         15x

  9 ≥  x

   x ≤ 9

Answer: D

66 < 2x + 28

<u>-28 </u>  <u>        -28 </u>

38 <  2x

 19 <  x

  x > 19

Answer: C  <em>the answer could also be B</em>

11 < 5 + 2x

<u>-5</u>  <u>-5         </u>

6 <       2x

3  <  x

x > 3

Answer: E   <em>the answer could also be A, B, and C</em>

-30 ≥ 6 - 4x

<u>  -6</u>   <u> -6      </u>

-36 ≥    -4x

  9 ≤ x

   x ≥ 9

Answer: A

\frac{x}{12} - 4 ≥ 5

<u>       + 4 </u>  <u>+ 4 </u>

\frac{x}{12}    ≥ 9

12(\frac{x}{12}) ≥ 12(9)

 x   ≥ 108

Answer: B

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Factorize: x² + 3x + 2​
zvonat [6]

Step-by-step explanation:

x² + 3x + 2

x² + x + 2x + 2 because 1+2=3 and 2×1=2

By taking out common terms, we get

x(x+1)+2(x+1)

(x+1)(x+2)

7 0
3 years ago
1)-11 + __ = 15<br> I really need help
katrin [286]

Answer:

26

Step-by-step explanation: You basically add 11 them you are at 0 then add 15 to that number and you get 11+15=26 thats ur answer

6 0
3 years ago
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Complete the table <br> y=1/4x-2
igomit [66]

Answer:

-4, -3, -2, -1, 0

Step-by-step:

1st: 1/4(-8) - 2 = -4 = y

2nd: 1/4(-4) - 2 = -3 = y

3rd: 1/4(0) - 2 = -2 = y

4th: 1/4(4) - 2 = -1 = y

5th: 1/4(8) - 2 = 0 = y

4 0
2 years ago
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Find the solutions of the quadratic equation -9c² +2 +3 = 0.
Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a = -9, b = 2 and c =3

Put the values,

c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69

So, the solution are -0.47 and 0.69.

8 0
3 years ago
Add and round to the correct number of significant digits: 13.8 + 60 A.70
ArbitrLikvidat [17]
The correct answer is C
6 0
4 years ago
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