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Katyanochek1 [597]
3 years ago
14

Simplify (4x+5y)(2x-3y)+3xy Help

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

8x² - 15y² + xy

Step-by-step explanation:

(4x + 5y) (2x - 3y) + 3xy

multiplying the terms in brackets

(4x) (2x - 3y) + (5y) (2x - 3y) + 3 xy

multiplying with each terms inside the bracket

(4x)(2x) - (4x) (3y) + (5y) (2x) - (5y) (3y) + 3xy

doing the product each of the pair of terms

8x² - 12xy + 10xy - 15y² + 3xy

taking the sum of terms with coefficient "xy"

8x² - 15y² -2xy + 3xy

8x² - 15y² + xy


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3 years ago
What is the equation of the line that passes through the point (-2,2) and (0,5)? A. Y=-3/2x+5 B.Y=x-5 C.Y=3/2x+5 D. Y=x+5
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A bag contains 3 yellow, 1 red, 2 green beads. Charlene draws a bead, keeps it out, then draws another bead. What’s the probabil
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5 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
7 0
3 years ago
When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

\left( { - 5} \right)&#10;\cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot&#10;\left( { - 5} \right)

 

 

\left( { - 5} \right)&#10;\cdot \left( { - \frac{1}{5}} \right) = 1

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

5 0
3 years ago
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