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3 years ago

Olve: Mrs. Schippert made 6 withdrawals of $45 each time from

Mathematics

1 answer:

andrezito [222]3 years ago

7 0

Answer:

ms Schippert took $270

Step-by-step explanation:

45*6=270

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3 years ago

Read 2 more answers

A researcher wishes to estimate, with 9090% confidence, the proportion of adults who have high-speed Internet access. Her es

Sunny_sXe [5.5K]

Answer: a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : $z_{\alpha/2}=1.645$

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219$

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

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Required minimum sample size= 271

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3 years ago

Please simplify n-2/n^2-4

Doss [256]

Answer:

$\frac{1}{ {n} + {2}}$

Step-by-step explanation:

$\frac{n - 2}{ {n}^{2} - 4} \\ \\ = \frac{n - 2}{ {n}^{2} - {2}^{2} } \\ \\ = \frac{n - 2}{ ({n} + {2})({n} - {2})} \\ \\ = \frac{1}{ {n} + {2}} \\$

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