Find the circumference given the area = 113.1 ft². Use 3.14 for π as necessary.
2 answers:
The circumference of the circle is 37.68 ft
Step-by-step explanation:
Given,
The area of the circle is 113.1 sq ft
To find the circumference of the circle we need to find the radius of the circle first
Formula
The area of circle with radius r is = π sq unit
The circumference of circle with radius r is = 2πr unit
Let us take the radius of the circle is r ft
According to the problem,
π
or,
or,
or, r =
or, r = 6
Now,
The circumference of the circle is 2×3.14×6 ft = 37.68 ft
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Answer:
Step-by-step explanation:
We have given:
E is (-1,6) and F is (3,9)
And ratios are 3:2
We will use the section formula to find the required coordinates:
section formula=
Here,
On substituting the values in the formula we get:
Hence, required coordinates are:
Answer:
Unpaid balance = $56.96
Finance charge = $0.8544
New balance =$171.7944
Step-by-step explanation:
Given : Previous balance = $91.96
Payments/credits = $35.00
Monthly rate = 1.5%
New purchases = $113.98
To calculate : The unpaid balance, finance charge, and new balance using the unpaid balance method.
Solution :
Unpaid balance = Previous balance - Payments
Unpaid balance = $91.96- $35
Unpaid balance = $56.96
We have given rate of interest= 1.5%=0.015
Finance charge = Finance rate × Unpaid balance
Finance charge =
Finance charge = $0.8544
New balance = Unpaid balance + finance charge + new transaction
New balance = $56.96 +$0.8544+ $113.98
New balance =$171.7944
Take the derivitive
f'(x)=6x^2+2x-11
find where f'(x)=0
f'(x)=0 when x=-1.53089 or x=1.19756
we use a sign chart
test values to see where the signs are
(see attachment)
f'(-2)=(+)
f'(0)=(-)
f'(2)=(+)
max happens when sign changes from (+) to (-)
min happens when sign changes from (-) to (+)
according to the chart, max is at -1.53089 and min is at 1.19756
now evaluate the original function for x=-1.53089 and x=1.19756
f(-1.53089)=12.0078
f(1.19756)=-8.30405
max at (-1.53089,12) and min at (1.19756, -8.30405)
I may have rounded off differently, but
answer is 2nd option
f'(x)=6x^2+2x-11
find where f'(x)=0
f'(x)=0 when x=-1.53089 or x=1.19756
we use a sign chart
test values to see where the signs are
(see attachment)
f'(-2)=(+)
f'(0)=(-)
f'(2)=(+)
max happens when sign changes from (+) to (-)
min happens when sign changes from (-) to (+)
according to the chart, max is at -1.53089 and min is at 1.19756
now evaluate the original function for x=-1.53089 and x=1.19756
f(-1.53089)=12.0078
f(1.19756)=-8.30405
max at (-1.53089,12) and min at (1.19756, -8.30405)
I may have rounded off differently, but
answer is 2nd option