Question

If AC = 5 cm, BC = 12 cm, and, the radius of the circumscribed circle is blank cm and m∠OAC = blank °. PLZ help I need help its Plato.!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 1

Answer:

radius = 6.5

<OAC = 67.38 degrees

Step-by-step explanation:

It looks like you are assuming 0 is on AB and in fact defines the circumradius of the circle. Further you are assuming (I think) that ABC is a right angle triangle.

Therefore AB^2 = AC^2 + BC^2

AB^2 = 5^2 + 12^2

AB^2 = 25 + 144

AB^2 = 169

AB = 13

AO is therefore 1/2 of 13 = 6.5.

CO is also 6.5 since all radii are equal.

I don't know if you know this but the only way you can solve this is to use the Cosine Law for distance.

• AC = 5
• OC = 6.5
• OA = 6.5
• <CAO = ??

CO^2 = OA^2 + CA^2 - 2*OA*CA*Cos(<CAO)

6.5^2 = 6.5^2 + 5^2 - 2*5*6.5*Cos(<CAO)

42.25 = 42.25 + 25 - 65*Cos(<CAO)

0 = +25 - 65*Cos(<CAO)

-25 = -65*Cos(<CAO)

0.3846 = Cos(<CAO)

<CAO = cos-1(0.3846)

<CAO = 67.38 degrees.

Answer 2

Answer:

answer is 6,5 and 70 degrees.

Step-by-step explanation:

took the test