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Yuri [45]
3 years ago
14

it takes Zack 15 minutes to walk 7 1\2 blocks to the swimming pool. at this rate, how many blocks can he walk in one minute?​

Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

1/2 of a block

Step-by-step explanation:

Use proportions to solve

7.5 blocks / 15 minutes = x blocks / 1 minute

7.5=15x

x=.5

1. Multiply the numerators by the other's denominator( 7.5*1 will equal to 15*x)( * means times)

2. Isolate x by dividing 7.5=15x by 15 and you will have what x equals.

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A student wants to graph his earnings for each week during the next calendar year. He wants to see how his earnings change
Artyom0805 [142]

Answer:

Step-by-step explanation:

Line graph

8 0
3 years ago
National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea
kirill115 [55]

Answer:

The required expression is y=250,000-24,000 t

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m=\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}

Rate of change=m=\frac{Rise}{Run}=\frac{-240,000}{10}

Rate of change=m=\frac{Rise}{Run}=-24,000

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

(y-250,000)=-24,000(t-0)

y-250,000=-24,000 t

y=250,000-24,000 t

Hence, the required expression is y=250,000-24,000 t

6 0
3 years ago
Solve for f.<br> -f + 2 + 4f = 8 - 3f<br><br> f=
qwelly [4]
If you Simplify Both sides of the Equation, then Isolate the Variable 

F=1
3 0
3 years ago
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Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.e^{-\lambda.x}

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - e^{-\lambda.x}

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - e^{-0.0143.100}

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - e^{-0.0143.200}

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = \frac{1}{\lambda}

E(X) = \frac{1}{0.0143}

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = \sqrt{\frac{1}{\lambda^{2}} }

σ = \sqrt{\frac{1}{0.0143^{2}} }

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - e^{-0.0143*209.79})

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

\int\limits^m_0 f({x}) \, dx = 0.5

\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx = 0.5

\lambda.\frac{e^{-\lambda.x}}{-\lambda} = -e^{-\lambda.x} + e^{0}

1 - e^{-\lambda.m} = 0.5

-e^{-\lambda.m} = - 0.5

ln(e^{-0.0143.m}) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0
4 years ago
Ill give u brains :) PLZ HELP
ipn [44]

Answer:

Answer is B

Step-by-step explanation:

Just gotta find the mutliplaction between them

Givw brain now :)

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