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Katarina [22]
3 years ago
10

A sound wave travels through iron at a rate of 5120\,\dfrac{\text{m}}{\text{s}}5120 s m ​ 5120, start fraction, start text, m, e

nd text, divided by, start text, s, end text, end fraction. At what rate does the sound wave travel in \dfrac{\text{km}}{\text{h}} h km ​ start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction? \dfrac{\text{km}}{\text{h}} h km ​
Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

18432 km/h

Step-by-step explanation:

It is given that a sound wave travels through iron at a rate of 5120 m/s.

We know that

1 km = 1000 m

1 hour = 60 minutes

1 minutes = 60 second

Using these conversions we get

1 m = 0.001 km

1 hour  = 3600 second

5120\text{ m/s }=5120\times 0.001\times 3600\text{ km/h}

5120\text{ m/s }=18432\text{ km/h}

Therefore, the sound wave travels through iron at a rate of 18432 km/h.

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The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

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MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0
3 years ago
. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
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Answer:

t(h)= (h-200)/-4.9

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Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

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The time to reach a height of 50 meters is 30.6 seconds

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Give examples to explain the properties of real numbers

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3 years ago
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