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dimaraw [331]
3 years ago
9

PLEASE ANSWER ASAP 20 POINTS + BEST GETS CHOSEN AS BRAINLIEST

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0
f(x)=x+4\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{(x+h+4)-(x+4)}{h}\\\\=\dfrac{x+h+4-x-4}{h}=\dfrac{h}{h}=1
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Can somebody pretty please help me please
Basile [38]

9514 1404 393

Answer:

  A.  $4006

Step-by-step explanation:

The total tax due is the sum of the amounts due in each applicable bracket.

  $970 +3,036 = $4,006

_____

<em>Additional comment</em>

There are easier ways to compute the tax, but this is the way shown on many tax forms.

7 0
3 years ago
Which postulate or theorem proves that these two triangles are congruent?
timofeeve [1]

what was the right answer?

3 0
3 years ago
**The sum of a number and 7.<br> divided by 3. is 2."
barxatty [35]

Answer:

-1

Step-by-step explanation:

7+(-1)= 6

6/3 = 2

There are no other solutions I can find to it. It says sum but technically you can add a negative number.

Don´t listen to me if you think that I am wrong. But I hope this helps!!

6 0
3 years ago
Find the domain of the rational expression: 4-x/3x+21
mafiozo [28]

(4-x) /(3x+21)

The denominator cannot be zero

3x + 21 ≠ 0

3x ≠ -21

x ≠ -7

The domain of the function will be all real number except -7

{x | x ≠ -7}

7 0
3 years ago
Find the first three terms of the arithmetic series described. n= 16 aₙ= 15 sₙ= -120.
creativ13 [48]

Answer:

The first three terms are -30, -27 and -24

Step-by-step explanation:

The formula for nth term of a arithmetic series is given by:

aₙ = a₁ + (n - 1)d

Substitute n = 16 in the given equation:

a₁₆ = a₁ + (16 - 1)d

Where aₙ = a₁₆ = 15. Substitute in the given equation

15 = a₁ + 15d ⇒ Equation (i)

Sum of arithmetic sequence is given by:

Sₙ = n(a₁ + aₙ) / 2

Substitute n = 16 in the above equation:

S₁₆ = 16(a₁ + a₁₆) / 2

Where S₁₆= -120 and a₁₆=15, substitute:

-120 = 16(a₁ + 15)/2

-240 = 16(a₁ +15)

-15 = a₁ + 15

a₁ = -30

Substitute it in Equation (i)

15 = a₁ + 15d

15 = -30 + 15d

15d = 15+30

d = 45/15

d = 3

So

a₁ = -30

a₂ = a₁ + (2-1)d

a₂ = -30 + 3

a₂ = -27

a₃ = a₁ + (3-1)d

a₃ = a₁ + 2d

a₃ = -30 + 2(3)

a₃ = -30 +6

a₃ = -24

8 0
3 years ago
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