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ivanzaharov [21]
3 years ago
7

Please help will mark brainliest!!

Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Answer:

29

Step-by-step explanation:

180-151=29

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Jacob has some cookies. 3/4 of his cookies are chocolate chip. Out of the chocolate chip cookies 1/8 of them have nuts as well.
ryzh [129]
Well, we can find the answer by multiplying the two fractions. 3/4*1/8 equals 3/32.

7 0
3 years ago
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Find the geometric proof
GrogVix [38]

Answer:

See Explanation

Step-by-step explanation:

Line l is bisector of MO... (given)

\therefore MN = NO.... (1)

\because MN + NO = MO..(M-N-O)

\therefore NO + NO = MO..[From \:(1)]

\therefore 2NO = MO

\therefore NO = \frac{1}{2} MO

\therefore NO = \frac{1}{2}\times 24..(\because MO=24)

\therefore NO =12

Thus Proved

6 0
3 years ago
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Deirdre is factoring the polynomial x2 + 2x – 24. Which combination can she use to replace the middle term, 2x?
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3 years ago
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Delta furnishings received an invoice dated may 10 for a shipment of goods received june 21. The invoice was for a $8400.00 less
djyliett [7]

Answer:

The right solution is:

(a) $1,940

(b) $2,813

Step-by-step explanation:

Given:

Invoice amount

= $8,400

Discount 1

= 33.33%

Discount 2

= 12.5%

So,

The net payable amount will be:

= 8400\times  [1 - \frac{100}{300} ]\times [1 - \frac{12.5}{100} ]

= 8400\times \frac{2}{3}\times 0.875

= 4900 ($)

Now,

(a)

Amount paid will be:

= 2000\times 0.97

= 1940 ($)

Balance still to be paid will be:

= 4900-2000

= 2900 ($)

(b)

Amount paid will be:

= (4900- 2000)\times 0.97

= 2900\times 0.97

= 2813 ($)

Balance still to be paid will be:

= 2000 ($)

Thus the above solution is the appropriate one.

6 0
3 years ago
A population of 200 animals is decreasing by a rate of .96 per year . At this rate, in how many years will the population be les
mojhsa [17]
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ

Now, we need to know when the population will be less than 170.

So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n

n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
7 0
3 years ago
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