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enot [183]
4 years ago
11

50 students in 4 buses. how many is in each bus

Mathematics
1 answer:
Taya2010 [7]4 years ago
7 0
There are 14 students on 3 of the buses and 8 on the other
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I need help please as fast as possible
tankabanditka [31]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hdhdbdudndhdbdudbs bdhdhdhdhdbd
garik1379 [7]

Answer:

Dang I forgot how to do that

7 0
3 years ago
Find the product. <br> (y-3)(y-4)=
zubka84 [21]

Answer:

<u>y^2+12-7y</u>

Step-by-step explanation:

(y-3)(y-4)

I will split it up for us

y*y= <u>y^2</u>

-3*y= -3y. \

y*-4= -4y. / <u>-7y</u>

-3*-4= <u>12</u>

<u>y^2+12-7y</u>

7 0
3 years ago
(x^2−x−6x^2−8x+16)/(x2−x−12)
erma4kov [3.2K]

-3 and 4 cannot be the values of x in the given expression

The expression is given as:

\frac{(x^2-x-6x^2-8x+16)}{(x^2-x-12)}

Start by equating the denominator to 0

x^2 - x - 12 = 0

Expand the above equation

x^2 - 4x + 3x - 12 = 0

Factorize the equation

x(x - 4) + 3(x - 4) = 0

Factor out x - 4

(x + 3) (x - 4) = 0

Split

(x + 3)= 0\ or\  (x - 4) = 0

Remove brackets

x + 3= 0\ or\  x - 4 = 0

Solve for x

x =- 3\ or\  x = 4

Hence, -3 and 4 cannot be the value of x in the given expression

Read more about expressions at:

brainly.com/question/2972832

5 0
3 years ago
I need help with this question please and thank you
inna [77]

d-13=5 is actually suppose to be solved liek this:

d - 13 = 5

   +13   +13

The absoulte value of 13 is 13, it is negative so you have to add 13 to get to 0 so it can be cancelled out.

5 0
3 years ago
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