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raketka [301]
3 years ago
15

An introductory APR is the interest that applies to _____.

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0
It’s C cash advances after the introductory period.
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Whats x? Problem:2x+7=11-2x
koban [17]
2x+7=11-2x (add 2x)
4x+7=11 (minus 7)
4x=4 (divide by 4)
x=1
8 0
4 years ago
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50 POINTS!! BRAINLIEST TO THE FIRST ANSWER!!
JulijaS [17]

Answer:

i really dont know but yeh

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3 years ago
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Find the side lengths in the following triangle.
faltersainse [42]

Answer:

I'm not too sure which one you need, so choose what answer needs to go in the box!

JL= 44.5

JK=23.3

KL=23.3

Step-by-step explanation:

Since JK and KL are equal to eachother, we have to find the missing variable through them. You want to choose one side to have the variable number and the other side for the normal numbers. I can't really explain this next bit, so I'll show the math below:

V N

4x - 10.7 = 2x + 6.3

+10.7. +10.7

_________________

4x = 2x + 17

-2x -2x

2x = 17

So, once there is only one variable number and one normal number left, what do you do? You divide the variable by the number it's worth and carry the division to the normal number.

2x = 17

÷2. ÷2

_______

x = 8.5

So, 8.5 is our number we need. We then just insert it into all the equations to get the numbers.

4 × 8.5 = 34

34 - 10.7 = 23.3

Since JK and KL are equal, they are both 23.3.

5 × 8.5= 42.5

42.5 + 2 = 44.5

JL=44.5

8 0
3 years ago
Find the inverse of the matrix <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%5C%5C-10%269%5C%5C
valentinak56 [21]

Answer:

The answer is (b)

Step-by-step explanation:

* Lets check how to find the inverse of the matrix,

 its dimensions is 2 × 2

* To know if the inverse of the matrix exist find the determinant

- If its not equal 0, then it exist

* How to find the determinant

- It is the difference between the multiplication of

 the diagonals of the matrix

Ex: If the matrix is \left[\begin{array}{ccc}a&b\\c&d\end{array}\right]

     its determinant = ad - bc

- After that lets swap the positions of a and d, put negatives

 in front of b and c, and divide everything by the determinant

- The inverse will be \left[\begin{array}{ccc}\frac{d}{ad-bc} &\frac{-b}{ad-bc}\\\frac{-c}{ad-bc} &\frac{a}{ad-bc}\end{array}\right]

* Lets do that with our problem

∵ The determinant = (9 × 9) - (-2 × -10) = 81 - 20 = 61

- The determinant ≠ 0, then the inverse is exist

∴ The inverse is \frac{1}{61}\left[\begin{array}{ccc}9&2\\10&9\end{array}\right]=

   \left[\begin{array}{ccc}\frac{9}{61}&\frac{2}{61}\\\frac{10}{61} &\frac{9}{61}\end{array}\right]

* The answer is (b)

7 0
3 years ago
Find the surface area of the rectangular prism
nika2105 [10]

The team go skirt pop pop pop pop pop pop...

8 0
3 years ago
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