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Angelina_Jolie [31]

4 years ago

13

the first term of an arithmetic sequence is 5 . the 12 th term is 137 . what is the common difference of the arithmetic sequence

?

1 answer:

valentina_108 [34]4 years ago

7 0

5,x,x,x,x,x,x,x,x,x,x,137

137-5=132

132/12=11

The common difference is 11

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Answer:

8 grams

Step-by-step explanation:

The balance is in equilibrium, so the weights of the two sides are equal.

Let the weight of a square be s.

Left side: 2s + 4

Right side: s + 3(4) = s + 12

The weights are equal, so we set the two expressions equal.

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s = 8

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Answer:

(7a^2 + 8b^2 + 5ab) (7a^2 + 8b^2 - 5ab)

Step-by-step explanation:

Dado que ambos términos son cuadrados perfectos, puede factorizar utilizando la fórmula de la diferencia de cuadrados, a^2 - b^ 2 = (a + b) (a - b), donde a = 7a^2 + 8b^2 y b = 5ab.

English: Since both terms are perfect squares you can factor using the difference of squares formula, a^2 - b^2 = (a + b)(a - b), where a = 7a^2 + 8b^2 and b = 5ab.

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