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4 years ago

Find the measures of angles 1, 2, and 3 for the parallelogram

Mathematics

1 answer:

aliya0001 [1]4 years ago

3 0

In this parallelogram, by definition angles 2 and 3 are alternate interior and have the same measure, and angle 1 and 37degrees have the same measure. So angle 1 = 37. the other angle inside there that's not marked is supplementary with 63, so it measures 180 - 63 = 117. So angle 3, then, by the Triangle angle-sum theorem measures 180 - 37 - 117 = 26. As stated earlier, angles 2 and 3 are the same, so 2 is also 26. And I think we got them all! 1=37, 2 and 3 = 26.

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Which equation is equivalent to startroot x^2 + 81 EndRoot = x + 10?

Nitella [24]

Answer:given below

Step-by-step explanation:

sqrt x^2 +81= x + 10

x^2 + 81 = (x+10)^2

x^2 + 81 = x^2 + 20x + 100

so answer is:

x^2 + 81 = x^2 +20x + 100

..HOPE IT HELPS YOU...ALL THE BEST

3 0

3 years ago

A line segment has endpoints Q(-16, -12) and R(21, -8).

gulaghasi [49]

Answer:

(2.5, - 10 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

here (x₁, y₁ ) = (- 16, - 12 ) and (x₂, y₂ ) = (21, - 8 ) , then

midpoint = ( $\frac{-16+21}{2}$ , $\frac{-12-8}{2}$ ) = ( $\frac{5}{2}$ , $\frac{-20}{2}$ ) = (2.5, - 10 )

4 0

2 years ago

One year ago, Joan was five times as old as her pony. In one year's time, the sum of the ages will be 22. How old is Joan now?

iogann1982 [59]

Answer:

22 divided 5 I would think

Step-by-step explanation:

4 0

3 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

6 0

3 years ago

How did you find six things in triangle

AVprozaik [17]

Sorry it's a bit messy. but I hope you understand and it will help

7 0

3 years ago