Question

The Chapin Social Insight Test evaluates how accurately the subject appraises other people. In the reference population used to develop the test, scores are approximately normally distributed with mean 25 and population standard deviation five. The range of possible scores is between 0 to 41. Determine the standardized value (z-value) for the score of 28.

Answer 1

Answer: 0.6

Step-by-step explanation:

Formula to get the standardized value :

$z=\dfrac{x-\mu}{\sigma}$  (1)

, where x= random variable , $\mu$ = Population mean and $\sigma$ = population standard deviation.

As per given , we have

$\mu=25$

$\sigma=5$

To find standardized value for the score of x=28

$z=\dfrac{28-25}{5}=0.6$   (substitute values in (1))

Hence, the standardized value for the score of 28 is 0.6 .