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olya-2409 [2.1K]
3 years ago
15

Need help!! don't post none helpful answer or I will report you

Mathematics
2 answers:
Sergio039 [100]3 years ago
5 0
The second bubble on your problem
Andrews [41]3 years ago
3 0

Answer:

c  ±sqrt(x-16)

Step-by-step explanation:

To find the inverse of an equation, interchange x and y and solve for x

y = x^2 + 16

becomes

x = y^2 + 16

Subtract 16 from each side

x-16 = y^2

Take the square root of each side

±sqrt(x-16) = sqrt(y^2)

±sqrt(x-16) = y

The inverse  is ±sqrt(x-16)

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Mr. O'Brien is paid $7.30 per hour for the first 40 hours he works in a week. he is paid 1.5 times that rate for each hour after
nikklg [1K]
No it would be $481. 80 because of the 1.5. you ar3 supposed to do 7.30 times 44 and then equals 321.20 so you times that by 1.5
7 0
3 years ago
A man bought a refrigerator, an air conditioner, a TV set and a gas cooker for $150.00, $400.00, $180.00 and $300.00 respectivel
MaRussiya [10]

Answer:

1184.5

Step-by-step explanation:

150+400+180+300=1030

1030 × 15% = 154.5

(15% is also 0.15)

1030 + 154.5 = 1184.5

I hope this helps you :)

4 0
3 years ago
What is the value of the expression below? 3/8+(-4/5)+(-3/8)+5/4
Crazy boy [7]
It will help you!

=-17/40+-3/8+5/4

= -4/5+5/4

= 9/20 

And the answer is 9/20 or decimals (0.45)

4 0
3 years ago
Read 2 more answers
For the function f(x)=(1/2)⋅6^x , identify the domain, range, y-intercept, and asymptote.
skelet666 [1.2K]

Answer:

Step-by-step explanation:

f(x) = (1/2) *6^x = 2^-1 * 2^x *3^x

y= 2^ (x-1) * 3^x

Domain represents all values that x can have and is all real numbers

Range all values that y can have and is y > 0 ( all real numbers that are positive)

The y-intercept is the point where the graph intersects the y-axis so x=0 there

y = 2^(0-1) *3^0 = 1/2 *1 = 1/2

the asymptote is at y= 0

6 0
3 years ago
If the simple interest on ​$7,000 for 7 years is ​$2,940​, then what is the interest​ rate?
ddd [48]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$2940\\ P=\textit{original amount deposited}\dotfill & \$7000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &7 \end{cases} \\\\\\ 2940=7000(\frac{r}{100})(7)\implies \cfrac{2940}{7000(7)}=\cfrac{r}{100}\implies \cfrac{3}{50}=\cfrac{r}{100} \\\\\\ 300=50r\implies \cfrac{300}{50}=r\implies \stackrel{\%}{6}=r

4 0
3 years ago
Read 2 more answers
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