Ok there are 48000 mL in 48L.
A swimming pool and deck are built in a rectangle with length 40 ft and width 18 ft. If the pool itself is 320 square feet, what
2 answers:
Answer: The answer is (B) 400 square feet.
Step-by-step explanation: Given in the question that a swimming pool and deck are built in a rectangle with length 40 ft and width 18 feet. The pool itself is 320 square feet. We are to find out the area of the deck.
The area of the rectangle in which the pool and deck are built is given by
The area of the pool is given by
Therefore, the area of the deck will be
Thus, the correct option is (B) 400 square feet.
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Answer:
3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).
Step-by-step explanation:
Let the First positive number be <em>x</em> and second positive number be <em>y.</em>
Triple of first number = 3<em>x</em>
double of second number = 2<em>y</em>
According to question,
3<em>x </em>+ 2<em>y</em> = 34
Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34
So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34
Now, 3<em>x </em>+ 2<em>y</em> = 34
3<em>x </em>= 34 - 2<em>y</em>
Let x = 10 and by substituting its value in above expression,
Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)
In the same way put x = 4 then,
3<em>x </em>= 34 - 2<em>y</em>
Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)
Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.