<span>X/9=-5
First: To get your x alone, and to get rid of your fraction you would multiply each side by 9.
You would get: x=-45 <That would be your answer
HOPE THIS HELPS! ^_^</span>
Options:
![A.\ (\frac{3}{2}, \frac{9}{2})](https://tex.z-dn.net/?f=A.%5C%20%28%5Cfrac%7B3%7D%7B2%7D%2C%20%5Cfrac%7B9%7D%7B2%7D%29)
![D.\ (\frac{1}{2}, \frac{1}{4})](https://tex.z-dn.net/?f=D.%5C%20%28%5Cfrac%7B1%7D%7B2%7D%2C%20%5Cfrac%7B1%7D%7B4%7D%29)
Answer:
![A.\ (\frac{3}{2}, \frac{9}{2})](https://tex.z-dn.net/?f=A.%5C%20%28%5Cfrac%7B3%7D%7B2%7D%2C%20%5Cfrac%7B9%7D%7B2%7D%29)
Step-by-step explanation:
Given
![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
Required
Determine which of the given points is not true
![A.\ (\frac{3}{2}, \frac{9}{2})](https://tex.z-dn.net/?f=A.%5C%20%28%5Cfrac%7B3%7D%7B2%7D%2C%20%5Cfrac%7B9%7D%7B2%7D%29)
Here
and ![y = \frac{9}{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B9%7D%7B2%7D)
Substitute these values in ![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
![\frac{9}{2} = (\frac{3}{2})^2](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B2%7D%20%3D%20%28%5Cfrac%7B3%7D%7B2%7D%29%5E2)
![\frac{9}{2} = \frac{3}{2}*\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B2%7D%20%3D%20%5Cfrac%7B3%7D%7B2%7D%2A%5Cfrac%7B3%7D%7B2%7D)
![\frac{9}{2} \ne \frac{9}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B2%7D%20%5Cne%20%5Cfrac%7B9%7D%7B4%7D)
<em>Both sides of the equation are not equal. Hence, this point do not line on the curve</em>
<em></em>
![B.\ (-1, 1)](https://tex.z-dn.net/?f=B.%5C%20%28-1%2C%201%29)
Here
and ![y = 1](https://tex.z-dn.net/?f=y%20%3D%201)
Substitute these values in ![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
![1 = (-1)^2](https://tex.z-dn.net/?f=1%20%3D%20%28-1%29%5E2)
![1=1](https://tex.z-dn.net/?f=1%3D1)
<em>Both sides of the equation are equal. Hence, this point line on the curve</em>
![C.\ (4, 16)](https://tex.z-dn.net/?f=C.%5C%20%284%2C%2016%29)
Here
and ![y = 16](https://tex.z-dn.net/?f=y%20%3D%2016)
Substitute these values in ![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
![16 = 4^2](https://tex.z-dn.net/?f=16%20%3D%204%5E2)
![16 = 16](https://tex.z-dn.net/?f=16%20%3D%2016)
<em>Both sides of the equation are equal. Hence, this point line on the curve</em>
![D.\ (\frac{1}{2}, \frac{1}{4})](https://tex.z-dn.net/?f=D.%5C%20%28%5Cfrac%7B1%7D%7B2%7D%2C%20%5Cfrac%7B1%7D%7B4%7D%29)
Here
and ![y = \frac{1}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
Substitute these values in ![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
![\frac{1}{4} = (\frac{1}{2})^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%3D%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![\frac{1}{4} = \frac{1}{2}*\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D)
![\frac{1}{4} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
<em>Both sides of the equation are equal. Hence, this point line on the curve</em>
<em>From the calculations above; only </em>
<em> do no lie on the curve</em>
Sondera cause he/she could get salmon and more but grichen cant cause he olny ordered from 1
<h3><u>Question:</u></h3>
Bruce bought two books one Book cost four more than three times the other, together the two books cost him 72
. find prices for the two books
<h3><u>Answer:</u></h3>
The price of books are $ 17 and $ 55
<h3><u>Solution:</u></h3>
Let "x" be the cost of one book
Given that one Book cost four more than three times the other
Then, other book cost = 4 + 3x
Also given that together the two books cost 72
cost of one book + cost of other book = 72
x + 4 + 3x = 72
The above equation is used to solve the problem
x + 4 + 3x = 72
4x + 4 = 72
4x = 72 - 4
4x = 68
x = 17
Thus cost of one book is $ 17
Then cost of other book is 4 + 3x = 4 + 3(17) = 4 + 51 = 55
The other book costs $ 55
Answer:
R = 30
Step-by-step explanation:
Given y is directly proportional to R² then the equation relating them is
y = kR² ← k is the constant of proportion
To find k use the condition when R = 4, y = 24, then
24 = k × 4² = 16k ( divide both sides by 16 )
1.5 = k
y = 1.5R² ← equation of proportion
When y = 1350 , then
1350 = 1.5R² ( divide both sides by 1.5 )
900 = R² ( take the square root of both sides )
= R , that is
R = 30