Answer:
A: P = 41100 - 590t
B: 34610
Step-by-step explanation:
equation = 41100-(41100-36380)/(2011-2003)t
plug it in
41100 - 590(2014-2003)=34610
Answer:
0.1151 = 11.51% probability of completing the project over 20 days.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Expected completion time of the project = 22 days.
Variance of project completion time = 2.77
This means that 
What is the probability of completing the project over 20 days?
This is the p-value of Z when X = 20, so:



has a p-value of 0.1151.
0.1151 = 11.51% probability of completing the project over 20 days.
Answer:
n=N-1
Step-by-step explanation:
You can start by imagining this scenario on a small scale, say 5 squares.
Assuming it starts on the first square, the grasshopper can cover the full 5 squares in 2 ways; either it can jump one square at a time, or it can jump all the way to the end and then backtrack. If it jumps one square at a time, it will take 4 hops to cover all 5 squares. If it jumps two squares at a time and then backtracks, it will take 2 jumps to cover the full 5 squares and then 2 to cover the 2 it missed, which is also 4. It will always be one less than the total amount of squares, since it begins on the first square and must touch the rest exactly once. Therefore, the smallest amount n is N-1. Hope this helps!