Answer:
7(b^2 -2)(b^2 +2)
Step-by-step explanation:
Factoring the common factor 7 from both terms, you get the difference of squares. That can also be factored.
v = 7(b^4 -4) = 7(b^2 -2)(b^2 +2)
The difference b^2-2 will have irrational factors, so does not meet the problem requirements. This is the factorization over integers.
If the question had asked what is 9/9 closer to you would say 1. When you increase the numerator by one digit go higher than 1.
10/9 = 1.11111111
so it is closer to 1 than to anything else
Angle R is congruent to Angle Y
Side QR is congruent to side XY
