Question

7 (r3+15r² +48r – 44) = (r+6)​

Answer 1

Answer:

r=−9.403283,−6.348173,0.751456

Step-by-step explanation:

Let's solve your equation step-by-step.

7(r3+15r2+48r−44)=r+6

7r3+105r2+336r−308=r+6

Step 1: Subtract r+6 from both sides.

7r3+105r2+336r−308−(r+6)=r+6−(r+6)

7r3+105r2+335r−314=0

Step 2: Use cubic formula.

r=−9.403283,−6.348173,0.751456

Answer 2

Answer:

$\frac{-178 + and - \sqrt{64654} }{105}$

Step-by-step explanation:

Advanced equations like these fit perfect to do the quadratic formula

first we must find a,b and c

A=$x^{2}$

B=constant multiplied by x

C=constant not multiplied by x

Alright now that we established that we need to format the equation to equal 0 so it will basically look like this $a^{2}$+b+c=0

First add like terms

7 (51r + $15^{2}$ -44) = r + 6

Then we do the distributive property

357r + $105r^{2}$ -308 = r + 6

Then we inverse the R + 6 so we can make the equation equal 0

so 357r + $105r^{2}$ -308-r-6 = 0

Add like terms again

356r + $105r^{2}$ -314=0

Now we have our A B and C!!! So lets put it in the quadratic formula

I like to find the discriminant first which is $b^{2} -4ac$ so lets plug everything in.

356$356^{2} -4(105)(-314)$

and that equals

258616 but that isn't a perfect square so we'll need to factor it so lets keep it fragmented for the time being

$\frac{-316+ and -\sqrt{356^{2}+131880 } }{210}$

is our current expression

The easiest thing to factor out is $2^{2}$

So that should equal

$\frac{-356+ and -\sqrt{2^{2} *64654} }{210}$

Square $2^{2}$

$\frac{-356+and-2\sqrt{64654} }{210}$

now the only thing left to do is divided every thing by the greatest common factor which is 2, we don't divided whatever is in the $\sqrt{x}$ when doing this step

so the final solution is

$\frac{-178+ and -\sqrt{64654} }{105}$