Answer:
A) Graph an quadratic equation for a parabola (x being to the power of 2), and a linear equation. Examples would be y=x² and y=x.
B) Parabolas that share the same vertex can simply have another transformation done to them. For example: y= 5x² and y=3x².
C) A line that would pass through these would be any linear graph WITHOUT a 'b' value, so a y intercept of 0. An example would be y=5x.
The answer must be C. the diagonals of a kite are perpendicular.
Quick note. perpendicular lines always form a 90° angles
Answer:
<em><u>Given :-</u></em>
Two legs of a rt. triangle : 8 and 10 respectively.
<em><u>To find :-</u></em>
Length of the hypotenuse
<em><u>Solution :-</u></em>
Using Pythagorean Theorem;
(hypotenuse)² = (8)² + (10)²
= 64 + 100
hypotenuse = √164
= 12.8 units
A=6a^2 is how you solve the surface area of a cube
To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3
Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3
Then you can divide 273 by 3 to get the final answer:
273/3 = 91
He will have 91 peaches overall.
Hope this helps! :)