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boyakko [2]
4 years ago
13

Se implicit differentiation to find an equation of the tangent line to the curve at the given point.7x2 + xy + 7y2 = 15, (1, 1)

(ellipse)
Mathematics
1 answer:
suter [353]4 years ago
5 0
F'(x, y) = 14x +xydy/dx + 14ydy/dx = 0
(xy+14y)|dy/dx = -14x
dy/dx = -14x /(xy+14y)
dy/dx |(x=1,y=1) : -14(1) / (1+14) = -14/15

using
y-y1=/x-x1 = -14/15
y-1/x-1 = -14/15
15y-15 = -14x+14
15y+14x -15-14=0
14x +15y = 29
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igor_vitrenko [27]

The distance between the ships changing at 92.29 Knots

  • Using the position of ship A as the reference point, at time t measured in hours past noon, ship A is 18 t miles west of this point and ship B is 40 + 17t north of this point.
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                              d(t) = \sqrt{(18t)^{2} + (40+17t)^{2} } \\

The rate of change of distance is -

                              \frac{dd}{dt} = \frac{36t + 2(40 + 17t)17}{2\sqrt{18t^{2} + (40 + 17t) } }

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To learn more about differentiation from the given link

brainly.com/question/25081524

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4 0
2 years ago
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The opción b

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3900=3.9k

7 0
4 years ago
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