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ICE Princess25 [194]
3 years ago
8

Simplify the number using the imaginary unit i: (square root) -28

Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

Answer:

C


Step-by-step explanation:

<em>Imaginary Number  i is defined as the square root of -1</em>

<em>We can write:  i=\sqrt{-1}</em>


Now, we want to simplify  \sqrt{-28}

<em>We can use the formula \sqrt{(a)(b)} =\sqrt{a} \sqrt{b} to simplify it further:</em>

\sqrt{-28} \\=\sqrt{(-1)(28)} \\=\sqrt{-1} \sqrt{28}

<em>Using the fact that i=\sqrt{-1}  ,  we can write:</em>

i\sqrt{28}

This is answer choice C.



olasank [31]3 years ago
3 0
<span>(square root) -28
=</span><span>(square root) 4*-7
=2</span><span>(square root)-7
hope this helps</span>
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  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

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From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

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===========================

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<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

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<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

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<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

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