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3 years ago

Help please!! asap!!

Mathematics

1 answer:

Llana [10]3 years ago

3 0

Answer: 1. 2 2. 4 3. 9

Step-by-step explanation: Hi there!

First, we need to set up our equation by combining like terms.

x+2x+4x+1=15

7x+1=15

Then subtract 1 on both sides

7x=14

Then divide by 7

x=2

So x=2

Put that into all of the x values on the piece of steel to get 2, 4, 9.

Hope this answer helps you!

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Name each polynomial 4m^2-5m+6 18s-7 6p^3

faltersainse [42]

Answer:

Quadratic function

linear function

cubic function

Step-by-step explanation:

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2 years ago

Is (10, 5) a solution to this system of inequalities? 20x + 4y > 5 x + y < 15

Sergio039 [100]

No, it is not a solution, as 15 is not less-than fifteen.

8 0

2 years ago

Benny has saved three thousand nine hundred cents over four days from selling lemonade.How many dollars does Benny have?

saw5 [17]

30 Dollars.

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6 0

2 years ago

Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.

-BARSIC- [3]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)$

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

$4^n+17$ is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so $4^k+17$ is divisible by 3

and we check what happens for k+1

$4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17$

$3\cdot 4^k$ is divisible by 3 and

$4^k+17$ is divisible by 3, by induction hypothesis

So, the sum is divisible by 3.

Step 3 - Conclusion

We just prove that $4^n+17$ is divisible by 3 for all positive integers n.

Thanks

4 0

3 years ago

A basketball player has made 6060% of his foul shots during the season. Assume the shots are independent.

motikmotik

Answer:

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

$E(X) = \frac{1}{P(X)}=\frac{1}{0.4} \\E(X) = 2.5\ shots$

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

$E=99*0.6\\E=59.4\ shots$

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

$s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots$

The standard deviation is 4.87 shots.

7 0

2 years ago