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3 years ago

Are these expressions the same c = 1cc + 1/4c why or why not

1 answer:

6 0

Yes 1c = c.

Technically, the "1" in front of the "c" is called an "implied 1" and, so it's simply written as c.

Here's, an example that should make this clear:
Say c = 4
Then (1)(c) = (1)(4) = 4 = c

1c + 1/4 c

What is a whole plus 1/4? 1 1/4 or 5/4
Same thing here:
c + 1/4 c or 1c + 1/4 c = 1 1/4c or 5/4c

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Please help me on question 6 please, please

fiasKO [112]

Answer:

7; 40

Step-by-step explanation:

No symbol for the term that you are solving for . I will use β

V = βwh Divide by (wh)

V/(wh) = β

β = V/(wh)

β = 735/(21 × 5) = 7

β = 3312/(11.5 ×7.2) = 40

6 0

3 years ago

A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.

Ratling [72]

Answer:

1)Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

2) Two critical values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) $z=-2.40$

4) $p_v =2*P(z$

5) Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

$\bar X_{men}=23$ represent the mean for the sample men

$\bar X_{women}=28$ represent the mean for the sample women

$\sigma_{men}=5$ represent the population standard deviation for the sample men

$\sigma_{women}=10$ represent the population standard deviation for the sample women

$n_{men}=25$ sample size for the group men

$n_{women}=30$ sample size for the group women

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

1）Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2）Determine the critical value(s).

Based on the significance level $\alpha=0.01$ and $\alpha/2=0.005$ we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40$

4）What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

$p_v =2*P(z$

5）Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

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3 years ago

Mark is measuring the size of his children’s hands. His daughter’s handspan is 7.38 inches, and his son’s handspan is 16.05 cent

aleksklad [387]

The answer is C on edgenuity

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3 years ago

Read 2 more answers

A fence on a hill uses vertical posts L and M to hold parallel rails N and P. ∠10 and ∠14 are alternate interior angles. What is

kherson [118]

The answer is B. Thank you:$))

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