Answer: 3 seconds
We are given the following function:
(1)
Where:
is the time the ball is in the air
the initial upward velocity
the initial height of the ball
is the final height of the ball. If no one catches it, this will be <u>zero</u>
So, equation (1) changes to:
(2)
Substituting the known values:
(3)
This is a quadratic equation in the form 
. In order to find we can use the quadratic formula for the roots:
(4)
Where 
, 
and 
Substituting this values in (4):
(5)
(6)
(7)
For 
:
(8)>>>> This result does not work for us because is negative
For 
:
(9)>>>This is the result
Therefore:
<h2> If no one catches the ball, it will be 3 s in the air</h2>
Answer:
For each test run, the minimum time is 45 mins or <u>3/4 ____</u> hours
and the maximum time is 67.5 minutes or <u>1 hour 7.5 minutes.</u>
Step-by-step explanation:
If x is the number of hours the robot is performing a test run, the equation that can be used to find the minimum and maximum time (in hours) for a test run is <u>15 mins for 1 mile</u>
For 4 miles the time is 1 hour
For 1 miles the time will be 1/4 hour
For 3 miles the time will be 3/4 hours
and for 4.5 miles the time will be 4.5/4 hours
Now reversing
1 hour = 4miles
15 mins= 1 mile
45 mins = 3 miles
30 mins = 2 miles
67.5 min= 4.5 miles
For each test run, the minimum time is ____ hours
the minimum distance is 3 miles and time taken is 45 mins
and the maximum time is ____ hours.
The maximum distance is 3+ 1.5= 4.5 miles and time taken is 67.7 minutues or 1 hour 7.5 minutes.
This is my work on the problem.
I hope this helps
