Symmetric Property of Equality
From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.
Easy
quadratic means 2nd degree
means highest power of exponent is 2
so like x^2
first one
we have 3x^3, that is 3rd degree,nope
2nd one
we have 8x^4, nope, that is 4th degree
3rd one
we have -x^2, yep
4th one, we have 9x^4, that is 4th degree
answer is 3rd one or p(x)=-5x-x^2
To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
Answer: 3.75
Step-by-step explanation:
