The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
Answer:
Dilate circle A by a scale factor of 3.
Step-by-step explanation:
Generally, similar figures have sides in the same ratio
3(5) = 15
When dilate A by factor 3, it will look exactly like B
Answer: 
Step-by-step explanation:
total sides = 6
p (rolling a 1) = 
p (rolling a 2) = 
Note:
or - add
and - multiply
∴ 
∴ 
hence, p (rolling a 1 or 2) =
Answer:
should be "d" though i haven't calculated it all exactly
Step-by-step explanation:
A : 85
B : 83
C : 82
D : 81
