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2 years ago

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I need an simpler explanation of the math problem: Charlie had 5times more stamps than ryan. They have1,608in all. How many more

stamps does Charlie have than ryan?

1 answer:

Molodets [167]2 years ago

5 0

Answer:

Charlie had 1340 more stamps than Ryan

Step-by-step explanation:

altogether, they have 1608 stamps.

Because if Charlie has 5 times more plus Ryan's portion equals 6 portion total.

Divide 1608 by 6 and that equals 268

Meaning that Ryan has 268 stamps.

To confirm, subtract 268 from 1608

this equals 1340.

268 * 5 = 1340

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

2 years ago

2767545 to the nearest ten

vovangra [49]

276550 hope this helps !

5 0

3 years ago

Read 2 more answers

Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista

Flauer [41]

Answer:

A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

a^2 = (12-6)^2 +3^2 = 45

a = √45 = 3√5

and

b^2 = (6 -2)^2 +4^2 = 32

b = √32 = 4√2

Then the total length, in grid squares, is ...

3√5 + 4√2 = 6.7082 +5.6569 = 12.3651

If each grid square is 1/4 mile, then 12.3651 grid squares is about ...

(12.3651 squares) · (1/4 mile/square) = 3.0913 miles

The proposed route is too long by 0.09 miles.

5 0

2 years ago

The expression 20z−8 factored using the GCF is

Free_Kalibri [48]

GCF of 20 and 8 is 4

4(5z - 2)

8 0

2 years ago

Read 2 more answers

Recall from Intermediate Algebra that two non-vertical lines are perpendicular if and only if they have negative reciprocal slop

OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is $y = -4 x$

Step-by-step explanation:

From the question we are told that

The line is $y = \frac{1}{4} x + 8$

The point is P(0,0 )

Generally the equation for a line is $yn = mx + c$

Now comparing this with the given equation we see that

$m =\frac{1}{4} = slope$

$C =8 = intercept$

Generally the slope of the perpendicular to the given line is mathematically evaluated as

$m_1 = - \frac{1}{m}$

=> $m_1 = - \frac{1}{ \frac{1}{4}}$

=> $m_1 = -4$

Generally from the univesal equation of a line and the given point we have that

y = mx + c at p(0,0) and $m_1 = -4$ is

0 = -4 (0 ) + c

=> c = 0

Hence the equation perpendicular to the line given at the point given is

$y = -4 x$

8 0

2 years ago