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Yuliya22 [10]
3 years ago
8

Which completely describes the polygon A. equilateral B. equiangular C. regular

Mathematics
2 answers:
hodyreva [135]3 years ago
6 0

Answer:

The most complete description would be "regular."

Step-by-step explanation:

A square is a polygon with all four sides congruent and all four angles congruent.  This is also the definition of a regular polygon.

NeTakaya3 years ago
6 0

Answer:

Option: C is the correct answer.

C. Regular.

Step-by-step explanation:

Square--

Geometrically, square is defined as a regular quadrilateral , which means that it has four equal sides and four equal angles measuring 90 degree each.

Square could also be defined as a rectangle with two adjacent sides equal.

Hence, the term that completely describe the given polygon i.e. square is:

Regular.

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Please Help
iVinArrow [24]

Answer:

hundredths; 81.73

Step-by-step explanation:

If the number underlined is two, then it will rounding to the hundredths place. Since the number after it is 7, which is greater than 5, we get 81.73.

5 0
2 years ago
If (x-2)(y-1)=3 and (x+2)(2y-5)=15,
daser333 [38]

Answer:

Equation 1, Multiplied by 2: 2x + 4y = 10

Equation 1, Multiplied by 2: 2x + 4y - 10 = 10 - 10

Equation 1, Multiplied by 2: 2x + 4y - 10 = 0

Equation 1, Multiplied by 2: 2x - 2x + 4y - 10 = 0 - 2x

Equation 1, Multiplied by 2: 4y - 10 = - 2x

Equation 1, Multiplied by 2: - 10 + 4y = - 2x

Notice that Equation 1 = Equation 2

One Solution

Equation 1: x - y = -10

Equation 2: 2x + 3y = 15

5 0
3 years ago
If a=i-2j and b= 2i - xj are parallel, then x is.....<br>a) 4 3 2 ) 2 d 4.​
cupoosta [38]

Answer:

x = 4

Step-by-step explanation:

a = i-2j

b = 2i-xj

1 = k•2

-2 = k•(-x)

=> 1/2 = k

=> (-2)/(-x) = k

=> 1/2 = (-2)/(-x) => 1/2 = 2/x => x = 4

7 0
3 years ago
Use the Divergence Theorem to compute the net outward flux of the field F=&lt;-2x,y,-2z&gt; across the surface S, where S is the
lutik1710 [3]

Answer:

The net outward flux across the boundary of the tetrahedron is: -4

Step-by-step explanation:

Given vector field F = ( -2x, y, - 2 z )

div F = \nabla F = ( i \dfrac{\partial }{\partial x }+ j \dfrac{\partial}{\partial y} + k \dfrac{\partial}{\partial z}) \langle -2x, y, -2z \rangle

div F = \nabla F = ( \dfrac{\partial }{\partial x }(-2x)+  \dfrac{\partial}{\partial y}(y) + \dfrac{\partial}{\partial z}(-2z))

= -2 + 1 -2

= -3

According to divergence theorem;

Flux = \int \int \int div \ \ (F) \ dv

x+y+z = 2; 1^{st}  Octant

x from 0 to 2

y from 0 to 2 -x

z from 0 to 2-x-y

= \int\limits^2_0 \int\limits^{2-x}_0 \int\limits^{2-x-y}_0 -3dzdydx

=-3 \int\limits^2_0 \int\limits^{2-x}_0 (2-x-y)dy dx

= -3 \int\limits^2_0[(2-x)y - \dfrac{y^2}{2}]^{2-x}__0 \ \ dx

= -3 \int\limits^2_0(2-x)^2 - \dfrac{(2-x)^2}{2} dx

= -3 \int\limits^2_0\dfrac{(2-x)^2}{2} dx = - \dfrac{3}{2} \int\limits^2_0(4-4x+x^2) dx

=- \dfrac{3}{2}(4x-x^2 + \dfrac{x^3}{3})^2_0

=- \dfrac{3}{2}(8-8+\dfrac{8}{3})

=- \dfrac{3}{2}(\dfrac{8}{3})

= -4

Thus; The net outward flux across the boundary of the tetrahedron is: -4

3 0
4 years ago
How many radians are in a straight angle
OlgaM077 [116]
A straight 'angle' is 180 degrees.

That's π radians.
5 0
3 years ago
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