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4 years ago

PLEASE HELP!!!

Mathematics

1 answer:

My name is Ann [436]4 years ago

8 0

<h3>Answer: D) g(x) is the graph of f(x) compressed vertically</h3>

The input is x while the output is y = f(x). If we multiply both sides of y = f(x) by 2/3, then we'll get (2/3)y = (2/3)f(x) = (2/3)x^2

We see that the new outputs are 2/3 the size of the original. So the graph is shorter and has been vertically squished or compressed. If we multiplied both sides by some number larger than 1, then the graph will be vertically stretched.

No reflection has been done because that only happens if we multiplied both sides by a negative value. The negative flips things around (from positive to negative or vice versa).

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4 years ago

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REY [17]

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3 years ago

Find an equation for the nth term of the arithmetic sequence.<br> 8,6,4,2,…

jarptica [38.1K]

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Step-by-step explanation:

hope this helps

7 0

3 years ago

What is the value of (7 + 2i)(3 - i)?

Harrizon [31]

There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
$(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}$

Imaginary numbers:
Using the result from earlier:
$21-i-2i^{2}$
Now since $i = \sqrt{-1}$ , then the expression becomes:
$21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i$

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4 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula