1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dennis_Churaev [7]
3 years ago
11

What is the answer to this problem 1/4(5b+11)=19

Mathematics
1 answer:
Svetach [21]3 years ago
5 0
1/4(5b + 11) = 19....multiply both sides by 4, eliminating the 1/4
5b + 11 = 19 * 4
5b + 11 = 76
5b = 76 - 11
5b = 65
b = 65/5
b = 13 <==

You might be interested in
A rectangle has an area of 616 m² and a width of 22m. What is its length?
daser333 [38]

Answer:

l=28m

w Width

22

m

A Area

616

m²

Using the formula

A=wl

Solving forl

l=A

w=616

22=28m

hope this will help you

make me brainliest

8 0
3 years ago
Read 2 more answers
Help asap pls
Svet_ta [14]

Answer:

Eating dinner and eating dessert are dependent events because

P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

P(dinner and desert) = 0.5 ⇒ answer A

Step-by-step explanation:

* Lets study the meaning independent and dependent probability  

- Two events are independent if the result of the second event is not

  affected by the result of the first event

- If A and B are independent events, the probability of both events  

 is the product of the probabilities of the both events

- P (A and B) = P(A) · P(B)

* Lets solve the question  

∵ There is a 90% chance that a person eats dinner

∴ P(eating dinner) = 90/100 = 0.9

∵ There is a 60% chance a person eats dessert

∴ P(eating dessert) = 60/100 = 0.6

- If eating dinner and dating dessert are independent events, then

 probability of both events is the product of the probabilities of the

 both events

∵ P(eating dinner and dessert) = P(eating dinner) . P(eating dessert)

∴ P(eating dinner and dessert) = 0.9 × 0.6 = 0.54

∵ There is a 50% chance the person will eat dinner and dessert

∴ P(eating dinner and dessert) = 50/100 = 0.5

∵ P(eating dinner and dessert) ≠ P(eating dinner) . P(eating dessert)

∴ Eating dinner and eating dessert are dependent events because

  P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

  P(dinner and desert) = 0.5

8 0
3 years ago
2x + 3 = -x + 12 <br><br> Solve the equation, explanation is good.
raketka [301]

Answer:

3

Step-by-step explanation:

2x + 3 = -x + 12

subtract 3 from both sides

2x = - x + 9

add x to both sides

3x = 9

divide by 3

x = 3

7 0
3 years ago
What is the length of the arch CH
Yakvenalex [24]

Answer:

147°

Step-by-step explanation:

The measure of arc CH is equal to the central angle it sees

the angles arc AH sees are BAC and CAH so the length of arc AH would be the sum of these two angles

90° + 57° = 147°

3 0
3 years ago
How to write 30000+300+3 in standard form​
Elis [28]

Answer:

30303

Step-by-step explanation:

math bro

7 0
3 years ago
Other questions:
  • State two numbers such that the lesser number is 25% less than the greater number
    5·2 answers
  • 1. (2 points) Solve each equation and write the answer on the line
    13·1 answer
  • A bottling company uses a filling machine to fill plastic bottles with a popular cola. The bottles are supposed to contain 300 m
    5·1 answer
  • Plz help me ............
    9·2 answers
  • (6x2y + 4xy2 − 2y3 + 6) + (x2y + 3y3 − 5)
    10·1 answer
  • The sum of three consecutive even integers is –78
    15·1 answer
  • Which similarity statements describe the relationship between the two triangles? Check all that apply.
    12·2 answers
  • Consider the absolute value inequality: |x - 6| &gt; 20. Will the graph of the solutions to the inequality result in an "and" or
    10·1 answer
  • Greg enjoys jogging 4 times a week. On the first day he jogs 3 1/2 miles. on the second day he jogs 3 2/3 miles. on the third da
    10·1 answer
  • Helen rolls a dice and flips a coin. <br> calculate the probability
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!