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Korolek [52]
3 years ago
11

During a research​ experiment, it was found that the number of bacteria in a culture grew at a rate proportional to its size. At

5​:00 AM there were 6 comma 000 bacteria present in the culture. At​ noon, the number of bacteria grew to 6 comma 500. How many bacteria will there be at​ midnight?
Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Noon is 12:00

5am to 12noon is 7 hours

6,000 to 6,500

It grew by 500 in 7 hours

So one hour it is 500/7

In 12 hours that is from 12noon to 12midnight it will be 12×500/7+6500 since at 12noon it was 6500 that will be 6500+857=7357

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Answer: 3

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y

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=

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(

x

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⇒

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⇒

3

x

−

2

y

−

15

=

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Note:

The equn.of line passing through  

A

(

x

1

,

y

1

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and

with slope

m

is

y

−

y

1

=

m

(

x

−

x

1

)3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

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y

+

3

=

3

2

(

x

−

3

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⇒

2

y

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6

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x

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3

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2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

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y

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Explanation:

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∙

x

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where m is the slope and b the y-intercept

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3

y

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−

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x

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1

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2

3

=

3

2

⇒

y

=

3

2

x

+

b

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is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

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2

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b

⇒

b

=

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2

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2

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y

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x

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2

←

equation of perpendicular lineExplanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

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x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

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x

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into the partial equation

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b

⇒

b

=

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=

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