1. Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5).<br><br> A. -6<br> B. 6<br> C. 8

Point P with coordinates (25,−13) is translated by the mapping statement (x,y) maps to (x−9,y+16). What are the coordinates for

BigorU [14]

The coordinates of image are: P'(16,3)

Step-by-step explanation:

Given point is :

P(25,-13)

The rule is:

(x−9,y+16)

Let P' be the image of P after applying the translation rule

So,

We have to subtract 9 from x- coordinate of P and add 16 to y coordinate of P

P(25,-13) => P'(25-9 , -13+16) => P'(16,3)

Hence,

The coordinates of image are: P'(16,3)

Keywords: Ordered pairs, Translation

Learn more about translation at:

#LearnwithBrainly

7 0

3 years ago

Vertical angles are equal. What is the degree <2 and <3?

enyata [817]

Answer:

Angle 2 is 145

Angle 3 (and 1) is: 35

Step-by-step explanation:

Angles together will create 360 degrees. 145*2 = 290. 360 -290 = 70

70/2 = 35

8 0

3 years ago

Read 2 more answers

Iready question help fast pls

abruzzese [7]

13 floors is the correct answer

8 0

3 years ago

Read 2 more answers

Helpp plss this needs to be done before 11:59 I’ll do anything for you just helpp

Alexus [3.1K]

Answer:

20=91.35*2

182$

21=17+18+15 vs 17+15+18

equal distributive property

Hope This Helps!!!

8 0

2 years ago

Read 2 more answers

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$

7 0

3 years ago

1. Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5). A. -6 B. 6 C. 8