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3 years ago

Find the equation of the line, where P is a point on the graph of the line. m=2/3 , P(3,5)

Mathematics

1 answer:

jeka57 [31]3 years ago

3 0

Answer:

y = 2/3x + 3

Step-by-step explanation:

y - 5 = 2/3(x - 3)

y - 5 = 2/3x - 2

y = 2/3x - 2 + 5

y = 2/3x + 3

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Find the area of the shaded region. Round to the nearest tenth.

AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

$Area \: of \: both \: squares \\ = {2}^{2} + {3}^{2} \\ = 4 + 9 \\ = 13 \: {cm}^{2} \\ \\ Area \: of \: both \: right \: \triangle s \\ = \frac{1}{2} \times (2 + 3) \times 2 + \frac{1}{2} \times3 \times 3 \\ = 5 \times 1+ 1.5 \times 3 \\ = 5 + 4.5 \\ = 9.5 \: {cm}^{2} \\ \\ Area \: of \:shaded \: region \\ = Area \: of \: both \: squares\\ - Area \: of \: both \: right \: \triangle s \\ = 13 - 9.5 \\ \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \: {cm}^{2} }}}$

7 0

3 years ago

Select the point that is a solution to the system if inequalities yx^2-6

labwork [276]

Answer:

The correct answer is A.

$A(0,-2)$

Step-by-step explanation:

Method 1

You just have to plot each point on the graph.

The one that falls within the solution region is the correct choice.

From the graph, $A(0,-2)$ falls within the solution region.

See graph

Method 2

If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.

The first inequality is

$y\:$

If we substitute $A(0,-2)$ , we get;

$-2\:$

This statement is true.

The second inequality is

$y\:>\:x^2-6$

If we substitute $A(0,-2)$ , we get;

$-2\:>\:(0)^2-6$

This gives,

$-2\:>\:-6$

This statement is also true.

8 0

3 years ago

Q # 6 please solve the equation

nevsk [136]

The answer is 314,000,000 ft^2

pi r^2

3.14* 10,000^2

3.14*100,000,000

314,000,000

6 0

4 years ago

Please help differentiate this!!!!!!!!!

vlada-n [284]

$\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t$

$\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3 \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}$

5 0

3 years ago

Read 2 more answers

Rewrite the rarional exponent as a radical by extending the properties of integer exponents

Nataly_w [17]

Answer: C

Step-by-step explanation:

Simplify the expression to 2^1/4

Now transform the expression using a^m/n = n root a raised to a power of m.

And that's how you get your answer.

3 0

3 years ago