The length of a rectangle is 6 m more than twice the width. if the area of the rectangle is 140m^2, find the dimensions

1 answer:

4 0

Length(l)= 2w+6
Width(w)= w
Area(A)= 140 m²
Area= l*w
140 = l*w
140= (2w+6)w
140= 2w²+6w( divide each side by 2)
70= w²+3w
w²+3w -70= 0
(^^^^^^Factor out expression)
(w-7)(w+10)= 0 (set each expression equal to zero and use the positive answer as the value for "w"(because a negative width is impossible))

w-7=0
w=7m

w+10=0
w= -10m (Impossible for a physical measurement to negative: therefore This "w" value is incorrect)

Use w=7 to find "l"
l= 2w+6
l=2(7)+6
l=14+6
l=20 m

Answer:
The dimensions of a rectangle are length and by width. For this rectangle the dimensions are 20 meters by 7 meters.
(width= 7 meters)
(length= 20 meters)

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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard d

Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 28, \sigma = 7.6$