Question

. DeShawn and Shawna each improved their

Answer 1

One hosta costs $7.

Step-by-step explanation:

Let,

Cost of one hosta = x

Cost of one ivy = y

According to given statement;

12x+5y=144   Eqn 1

6x+y=54    Eqn 2

In order to find cost of one hosta, we will eliminate y.

Multiplying Eqn 2 by 5;

$5(6x+y=54)\\30x+5y=270\ \ \ \ Eqn\ 3$

Subtracting Eqn 1 from Eqn 3

$(30x+5y)-(12x+5y)=270-144\\30x+5y-12x-5y=126\\18x=126$

Dividing both sides by 18

$\frac{18x}{18}=\frac{126}{18}\\x=7$

One hosta costs $7.

Keywords: linear equation, subtraction

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