M is the midpoint of CF for the point c(3, 4) and f (9, 8) find MG
1 answer:
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Let denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position
and velocity
Immediately after launch, the rocket is subject to gravity, so its acceleration is
where .
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,
(the integral of 0 is a constant, but it ultimately doesn't matter in this case)
and
b. The rocket stays in the air for as long as it takes until , where
is the
-component of the position vector.
The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):
c. The rocket reaches its maximum height when its vertical velocity (the -component) is 0, at which point we have
<h2>Hello!</h2>
The answer is: [-2,2]
<h2>Why?</h2>The range of a function shows where the function can exist in the y-axis.
To know the range of the function, we have to isolate x,
So
The only possible values that y can take go from -2 to 2. Taking values out of these values will give as result a non-real number.
Therefore,
The range of the function is [-2,2]
Have a nice day!