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3 years ago

Best Deal 1

Mathematics

2 answers:

kipiarov [429]3 years ago

7 0

Answer: The answer would be D.

like she said down there !

Step-by-step explanation:

german3 years ago

4 0

d. $0.53 because..

3/5.25 = 1/1.75

5/9.75 = 1.95

7/12.60 = 1.80

10/14.20 = 1.42

12/18.24 = 1.52

then do ;

most expensive deal - least expensive deal = how much he’ll save

1.95 - 1.42 = .53

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Given the recursive formula below what are the first five terms in the sequence.

notsponge [240]

$a_1 = a_0 + 4 = 4$

$a_2 = a_1 + 4 = 8$

$a_3 = a_2 + 4 = 12$

$a_4 = a_3 + 4 = 16$

$a_5 = a_4 + 4 = 20$

I hope this helps you

7 0

4 years ago

GOOD AT MATH!! PLEASE HELPPP

lutik1710 [3]

Answer:

D, roughly 9.4 units

Step-by-step explanation:

you can make the graph into a right triangle

with sides of $x, 5,$ and $8$

$A^{2} +B^{2} =C^{2}$

$5^{2} +8^{2} =x^{2}$

$25+64=x^{2}$

$89=x^{2}$

$\sqrt{89} = 9.43$

4 0

3 years ago

What is the radius of a right cone with height 15 cm in volume nine pi centimeters cubed

zavuch27 [327]

Volume = 9 * PI = 28.2743338823 
 Cone Volume = (π • r² • h) ÷ 3
radius^2 = 3 * 28.274 / (PI * 15)
radius^2 = 84.822 / 0.2094395102 
 radius^2 = 404.99
radius^2 = 405
radius = 20.125

Source:
http://www.1728.org/volcone.htm

6 0

3 years ago

A. 220 B. 55 C. 110 D. 25

dlinn [17]

Answer:

The answer should be C

3 0

3 years ago

In testing the hypothesis H 0 colon mu subscript D less or equal than 5 space v s. space H 1 colon mu subscript D greater than 5

malfutka [58]

Answer:

The null hypothesis failed to be rejected (P-value=0.014).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The null and alternative hypothesis are:

$H_0: \mu=5\\\\H_a:\mu> 5$

The significance level is α=0.01.

The sample has a size n=20.

The sample mean is M=9.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7.5}{\sqrt{20}}=1.677$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{9-5}{1.677}=\dfrac{4}{1.677}=2.385$

The degrees of freedom for this sample size are:

$df=n-1=20-1=19$

This test is a right-tailed test, with 19 degrees of freedom and t=2.385, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.385)=0.014$

As the P-value (0.014) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

3 0

3 years ago