Question

Multiply the binomials (6a^3-5) (4a^3-11a)

Answer 1

For this case we must multiply the following expression:

$(6a ^ 3-5) (4a ^ 3-11a) =$

We apply distributive property considering that:

$+ * + = +\\+ * - = -\\- * - = +$

So:

$6a ^ 3 * 4a ^ 3-6a ^ 3 * 11a-5 * 4a ^ 3 + 5 * 11a =$

To multiply powers of the same base, we place the same base and add the exponents.

$24a^ {3 + 3} -66a^ {3 + 1} -20a ^ 3 + 55a =\\24a ^ 6-66a ^ 4-20a ^ 3 + 55a$

Answer:

$24a ^ 6-66a ^ 4-20a ^ 3 + 55a$