I think that is a common garden snake
Genetics, blood type gene has two alleles, each allele has genotype A, B or O. The A and B are dominant, and O is recessive. So allele A combined with allele O is type A. Similarly, BO is type B, AA is type A, BB is type B, OO is type O, and AB is typeAB.
If both parents have type A blood, then the alleles could be AA or AO, thus the allele A frequency is 75%, allele O frequency is 25% for both parents.
So the chance of alleles OO is 25% × 25% = 6.25%,
alleles AA is 75% × 75% = 56.25%,
alleles AO is 75% × 25% = 18.75%,
alleles OA is 25% × 75% = 18.75%.
Since AA, AO and OA are blood type A, and OO is blood type O, thus their child has 6.25% chance to be blood type O and 93.75% chance to be blood type A.
The +/- is called the rhesus factor, with + being dominant, and - being recessive.
So if both parents are -, the kids are always -, otherwise the kids might be + or -.
Child Blood Type Estimate Table:
Father's Blood TypeABABOMother's
Blood
TypeAA/OA/B/AB/OA/B/ABA/OBA/B/AB/OB/OA/B/ABB/OABA/B/ABA/B/ABA/B/
The point at which the toxin would interrupt normal cell signalling in the pathway is the signal amplification.
This is because of the G-protein uncoupling and inhibition of signal amplification by pertusis toxin. Pertusis toxin released by the bacteria Bordetella pertusis and prevents signal that is amplifying from the protein. The G-protein coordinates the interaction between membrane bound receptor proteins and the effector proteins involved in the intracellular signalling. The toxin promotes the uncoupling of this heterotrimetric protein and also inhibits the amplification thus preventing the interaction of the receptor proteins and the second messengers.
