Answer:
Step-by-step explanation:
<u>P</u>arentheses <u>E</u>xponents <u>M</u>ultiplication <u>D</u>ivision <u>A</u>ddition <u>S</u>ubtraction
5X100=500 and 9X1=9 and 41/100=0.41 Then put them back into the equation
5X100+9X1+41/100=
500 + 9 + 0.41 = Now add. 509.41
Answer:

Step-by-step explanation:
Given
t = 2 to 7
Required
Find the average speed over these intervals
The function is not given; so, I'll represent the function as s(t)
When 

When 


This gives:


Answer:
see explanation
Step-by-step explanation:
Since BD bisects ∠ ABC , then
∠ ABD = ∠ DBC , substitute values
3x + 4 = 55 ( subtract 4 from both sides )
3x = 51 ( divide both sides by 3 )
x = 17
The following integers from the greatest to least are as follows:
+3, 0, -3, -2, -8
If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺