Answer:
q = -5
q = 5
Step-by-step explanation:
Since there is no constant value. This must be a special case.
So,
(q+5)(q-5
)
q = -5
q = 5
Solve for x. 5(x + 3)= 4(x -3)
2 answers:
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The answer is: 
.
____________________________________________
Explanation:
____________________________________________
We have: " 6⁻¹ * (-2)³ * (-4)⁻² = ? " ;
_______________________________________
Note: "6⁻¹ =
= 
" .
Note the following property of exponents:
____________________________________
a⁻ˣ =
; {x ≠ 0}.
____________________________________________
Note: (-2)³ = (-2)*(-2)*(-2) = 4*(-2) = -8 .
_______________________________________
Note: (-4)⁻² =
;
=
;
=
;
____________________________________
So; we have:
_____________________________________
6⁻¹ * (-2)³ * (-4)⁻² ;
=
;
→ Cancel out the "8" in the "numerator" (to a "1") ; and the "16" in the number (and change to a "2"); since: {"16÷8 = 2" ; and since: "{8÷8=1"} ;
→and we have:
;
= .
_____________________________________
→ The answer is: .
_____________________________________
____________________________________________
Explanation:
____________________________________________
We have: " 6⁻¹ * (-2)³ * (-4)⁻² = ? " ;
_______________________________________
Note: "6⁻¹ =
Note the following property of exponents:
____________________________________
a⁻ˣ =
____________________________________________
Note: (-2)³ = (-2)*(-2)*(-2) = 4*(-2) = -8 .
_______________________________________
Note: (-4)⁻² =
=
=
____________________________________
So; we have:
_____________________________________
6⁻¹ * (-2)³ * (-4)⁻² ;
=
→ Cancel out the "8" in the "numerator" (to a "1") ; and the "16" in the number (and change to a "2"); since: {"16÷8 = 2" ; and since: "{8÷8=1"} ;
→and we have:
=
_____________________________________
→ The answer is:
_____________________________________
