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leva [86]
3 years ago
14

Find the product (X+y)(6x—2y)

Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0
<span><span>(<span>x+y</span>)</span><span>(<span><span>6x</span>−<span>2y</span></span>)</span></span><span>  =<span><span>(<span>x+y</span>)</span><span>(<span><span>6x</span>+<span>−<span>2y</span></span></span>)</span></span></span><span>  =<span><span><span><span><span>(x)</span><span>(<span>6x</span>)</span></span>+<span><span>(x)</span><span>(<span>−<span>2y</span></span>)</span></span></span>+<span><span>(y)</span><span>(<span>6x</span>)</span></span></span>+<span><span>(y)</span><span>(<span>−<span>2y</span></span>)
  </span></span></span></span><span> =<span><span><span><span>6<span>x^2</span></span>−<span><span>2x</span>y</span></span>+<span><span>6x</span>y</span></span>−<span>2<span>y^2</span></span></span></span><span> 
  Answer = <span><span><span>6<span>x^2</span></span>+<span><span>4x</span>y</span></span>−<span>2<span>y^<span>2</span></span></span></span></span>
Kaylis [27]3 years ago
4 0

Answer:

 Answer = 6x^2+4xy−2y^2

Step-by-step explanation:

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A decibel is a logarithmic unit that can be used to measure the intensity of a sound. The function y = 10logx gives the intensit
Anna007 [38]

Answer:

The sound intensity of a whisper is 333.3 times the reference intensity

Step-by-step explanation:

Given : The function y = 10logx gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.

A whisper has a sound intensity of 30 decibels.

To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.

Solution :

Graph is attached which shows their intersection at (1000,30).

We can also verify by substituting value.

We have given that a whisper has a sound intensity of 30 decibels.

Therefore, y=30 , Let log base 10

y = 10logx

30 = 10logx                              

\frac{30}{10} =logx

3=logx

Logarithmic property log_{x}b=a \Rightarrow b=x^a

x=10^3

x=1000

The ratio of the intensity of the sound to a reference intensity is 1000 decibels

The sound intensity of a whisper is times the reference intensity is

\frac{1000}{3}=333.33

The sound intensity of a whisper is 333.3 times the reference intensity.

7 0
3 years ago
Read 2 more answers
Which COULD be the area of this parallelogram?
BaLLatris [955]

Answer:

1650 in

Step-by-step explanation:

base times height

50 times 33 = 1650 in

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Why do the functions f(x) = sin−1(x) and g(x) = cos−1(x) have different ranges?
Gnom [1K]
We Know that
For a function to have an inverse function, it must be one-to-one—that is, it must pass the Horizontal Line Test.

1. On the interval [–pi/2, pi/2], the function y = sin x is increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is one-to-one
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On the restricted domain [–pi/2, pi/2]  y = sin x has a unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
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the range of y=sin-1  x  in the domain [-1,1]  is [–pi/2, pi/2]  

1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]

On the restricted domain [0, pi]  y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x  in the domain [0, pi]  is [-1,1] 
the range of y=cos-1  x  in the domain [-1,1]  is [0, pi] 

the answer is

<span>the values ​​of the range are different because the domain in which the inverse function exists are different</span>  
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