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ziro4ka [17]
3 years ago
15

Is anyone able to see if there is a counterexample for the following argument in logic?

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

if A=B

B=/=C

No A=C

All C are not A

You might be interested in
Add: (3x2 - 5x + 6) + (9 - 8x - 4x2) A) 12x2 - 13x + 2 B) 7x2 + 3x - 3 C) 7x2 - 13x + 15 D) -x2 - 13x + 15
kati45 [8]

Answer:

D

Step-by-step explanation:

So we have the expression:

(3x^2-5x+6)+(9-8x-4x^2)

Combine like terms:

=(3x^2-4x^2)+(-5x-8x)+(6+9)

Add or subtract:

=(-1x^2)+(-13x)+(15)

Simplify:

=-x^2-13x+15

Our answer is D

4 0
3 years ago
In the 7th grade, 150 of the students are attending the dance. If this is 62.5% of the entire grade, how many 7th graders are th
JulijaS [17]

Answer:

244 students.

Step-by-step explanation:

Okay, so. We know 150 people of the 7th grade is coming and 62.5% is the entire of the 7th graders coming. We would multiply.

150 * 62.5% = 93.75

We would round it up. It is over 5, so it would be 94 students. Then we would add

150 + 94 = 244

There are 244 students in 7th grade.

3 0
3 years ago
Write the number as hundredths in fraction form and decimal form. 9/10
Agata [3.3K]
0.09

hope this helped!!
3 0
3 years ago
What two numbers add up to -13 and multiply to 36?
vodka [1.7K]
-4 and -9 is the correct answer
6 0
3 years ago
Read 2 more answers
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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