Answer:you get two answers. y+6=-7/4(x+5) or y-1=-7/4(x+5)
Step-by-step explanation:
By the way the 7/4 is negative if you could not tell. You get this answer by finding the slope which is 1- -6/-5- -1 and get -7/4. Then you plug it into the formula y-y1=slope(x-x1). When you plug it in you should get that answer.
Answer:
Let the number of popcorn be x and the number of drinks be y, then according to the question we have the following equation
.................> linear equation
To sketch the graph first we need to find two points on it.
EXAMPLE
put x=0, we get y=10
put y=0, we get x=6
Thus, we have points (0,10) and (6,0), now sketch a line through it .
Thus in the graph x - axis represents the number of popcorn and y axis represents the number of drinks.
The slope of the graph is
Step-by-step explanation:
Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
<u />
<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.
Answer:
$22.5
Step-by-step explanation:
The original price is $30 and it's on sale for 25% off. Since 25% is a quarter of the total price, I divided 30÷4=7.5. $7.5 is 25% of $30, so 7.5 is the amount taken off the original price. To find what Daysi paid, I subtracted 30-7.5=22.5. $22.5 is the result after the 25% off, so Daysi paid $22.5.
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2