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grin007 [14]
3 years ago
13

WILL GIVE BRAINLIST!!!!!Which correctly describes a cross section of the right rectangular prism if the base is a rectangle meas

uring 15 inches by 8 inches? Select three options..
A right rectangular prism with length 15 inches, width of 8 inches, and height of 6 inches.



A cross section parallel to the base is a rectangle measuring 15 inches by 8 inches.
A cross section parallel to the base is a rectangle measuring 15 inches by 6 inches.
A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.
A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 4 inches by 15 inches.
A cross section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.
Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

A cross-section parallel to the base is a rectangle measuring 15 inches by 8 inches.

A cross-section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.

A cross-section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.

Step-by-step explanation:

the cross sections that are parallel and perpendicular will have the same measurements as the non-intersected sides. the last one will be a diagonal so the intersected edge is 6 and it creates a right triangle so it must be larger than 15 inches.

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I don’t understand this question. Can anyone help? I need answers ASAP. Thanks for all the help
zavuch27 [327]

There's some unknown (but derivable) system of equations being modeled by the two lines in the given graph. (But we don't care what equations make up these lines.)

There's no solution to this particular system because the two lines are parallel.

How do we know they're parallel? Parallel lines have the same slope, and we can easily calculate the slope of these lines.

The line on the left passes through the points (-1, 0) and (0, -2), so it has slope

(-2 - 0)/(0 - (-1)) = -2/1 = -2

The line on the right passes through (0, 2) and (1, 0), so its slope is

(0 - 2)/(1 - 0) = -2/1 = -2

The slopes are equal, so the lines are parallel.

Why does this mean there is no solution? Graphically, a solution to the system is represented by an intersection of the lines. Parallel lines never intersect, so there is no solution.

7 0
3 years ago
Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jean
ella [17]

We will solve this by suing simultaneous equations,

⇒ 5s + 3j = 87

    4s + 2j = 64

Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

⇒ (5s + 3j = 87) × 4

    (4s + 2j = 64) × 5

∴ ⇒ 20s + 12j = 348

       20s + 10j = 320

Subtract both the equations. This is how your result (after subtraction) should look like,

  ⇒ 2j = 28

∴ ⇒ j = $14

Now replace the value of 'j' in one of the original equations,

⇒ 4s + 2(14) = 64

⇒ 4s + 28 = 64

⇒ 4s = 64 - 28

⇒ 4s = 36

∴ ⇒ s = $9

Therefore, one pair of jeans cost $14 and a shirt costs $9

Hope you understood! Feel free to ask me if you didn't understand a step.

5 0
2 years ago
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AnnZ [28]

Answer:

p^3  / q^12

Step-by-step explanation:

p^6 q^4

------------------

p^3 q^16

We know a^b / a^c = a^(b-c)

First with variable p

p^6 /  p ^3 = p^(6-3) = p^3

Then with variable q

q^4 / q^16 = q^(4-16) = q^-12  and a^-b = 1/ a^b = 1 /q^12

p^3 * 1/ q^12

p^3  / q^12

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