The first thing we must do in this case is to define variables.
We have then:
x: speed of the giraffe
x + 5: speed of the ostrich
By definition we have:
d = v · t
d / v = t
Where,
d: distance
v: speed
t: time
Since the time is the same then we have:
5 / (x + 5) = 4 / x
5x = 4 (x + 5)
Clearing x we have:
5x-4x = 20
x = 20 mph (speed of the giraffe)
x + 5 = 20 + 5 = 25 mph (speed of the ostrich)
Answer:
20 mph (speed of the giraffe)
25 mph (speed of the ostrich)
The answer is 140, you just add them up and it goes by 2.
Answer:
20
Step-by-step explanation:
Answer: 26 cups will fit in a dispenser that is 30 cm high.
Step-by-step explanation:
First of all, we know that the first cup in the stack (the bottom cup) will be ten centimeters high, and we know that for every cup that is added on top of that, .8 centimeter will be added to the height. So, if we want to find how many cups will be in the dispenser we do this simple math:
30 - 10 = 20 Because the first cup is ten centimeters, we have to subtract that from the dispenser height.
20/.8=25 To find how many cups will be stacked on top of the first cup, we divide the remaining height by .8, the height of every other cup.
Now that we know that there will be 25 cups stacked on top of the first, we add the bottom cup to the rest of them.
25 + 1 = 26 Cups.
Answer:
11 > n > 4
Step-by-step explanation:
Given any two sides of a triangle, we now that the sum of such sides MUST be greater than the measure of the remaining side. This is, given the three sides a, b and c, it must be that:
a + b > c
a + c > b
b + c > a
For our case:
7 + 4 > n (1) ---> 11>n
7 + n > 4 (2)
4 + n > 7 (3)
The 1 inequality says that the n side MUST be less than 11.
Now, pick the (3) inequality and subtract 4 in both sides:
4 + n -4 > 7 - 4
n > 3
So, the n side must be grater than 3.
Thus, the solution is:
11 > n > 3
As we are working with integers we now that the grater integer larger than 3 is 4, and the greater integer less than 11 is 10. So, the side must be equal or greater to 4 and equal or less than 10:
10 >= n >= 4